Practicing Success
The mass defect in a particular nuclear reaction is 0.3 grams. The amount of energy liberated in kilowatt hours is (Velocity of light = 3 × 108 m/s) |
1.5 × 106 2.5 × 106 3 × 106 7.5 × 106 |
7.5 × 106 |
$E=\Delta m . c^2 \Rightarrow E=\frac{0.3}{1000} \times\left(3 \times 10^8\right)^2=2.7 \times 10^{13}$ J = $\frac{2.7 \times 10^{13}}{3.6 \times 10^6}=7.5 \times 10^6$ kWh. |