Find the value of the following expression:
$\frac{(7.03)^3-0.027}{(7.03)^2+2.109+(0.3)^2}$
Answer & explanation
Correct answer: option 4
$\frac{(7.03)^3-0.027}{(7.03)^2+2.109+(0.3)^2}$
a3 - b3 = ( a - b ) ( a2 + b2 + ab )
( a - b ) = \(\frac{a^3 - b^3}{a^2 + b^2 + ab }\)
On comparing them =
a = 7.03
b = 0.027
a - b = 7.03 - 0.027 = 6.73