Find the value of the following expressi

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

Find the value of the following expression:

$\frac{(7.03)^3-0.027}{(7.03)^2+2.109+(0.3)^2}$

Options:

7.06

7.33

6.73

Correct Answer:

6.73

Explanation:

$\frac{(7.03)^3-0.027}{(7.03)^2+2.109+(0.3)^2}$

a³ - b³ = ( a - b ) ( a² + b² + ab )

( a - b ) = $\frac{a^3 - b^3}{a^2 + b^2 + ab }$

On comparing them =

a = 7.03

b = 0.027

a - b = 7.03 - 0.027 = 6.73