If cot y$=\frac{12}{5}$, then what is the value of $cos^2$y?
Answer & explanation
Correct answer: option 3
cot y = $\frac{12}{5}$
= $\frac{B}{P}$
B = 12, P = 5
H = $\sqrt{B^2 + P^2}$
= $\sqrt{144\;+\;25}$ = $\sqrt{169}$ = 13
cos y = $\frac{B}{H}$ = $\frac{12}{13}$
cos²y = $\frac{144}{169}$