Practicing Success
Practicing Success
CUET Preparation Today
If cot y$=\frac{12}{5}$, then what is the value of $cos^2$y? |
$\frac{72}{143}$ $\frac{72}{91}$ $\frac{144}{169}$ $\frac{84}{143}$ |
$\frac{144}{169}$ |
cot y = $\frac{12}{5}$ = $\frac{B}{P}$ B = 12, P = 5 H = $\sqrt{B^2 + P^2}$ = $\sqrt{144\;+\;25}$ = $\sqrt{169}$ = 13 cos y = $\frac{B}{H}$ = $\frac{12}{13}$ cos²y = $\frac{144}{169}$ |
