In the given figure BD perpendicular to AC then what will be the measure of angle AEB ?
Answer & explanation
Correct answer: option 1
We know that,
In ΔADO,
∠ADO + ∠DAO + ∠DOA = 180°
= 90° + 35° + ∠DOA = 180°
= 125° + ∠DOA = 180°
= ∠DOA = 180° – 125°
= ∠DOA = 55°
Now, ∠DOA = ∠BOE = 55°
In ΔBOE,
∠BOE + ∠OEB + ∠EBO = 180°
= 55° + ∠OEB + 45° = 180°
= ∠OEB = 180° – 45° – 55°
= ∠OEB = ∠AEB = 80°