In the given figure BD perpendicular to AC then what will be the measure of angle AEB ?

80°

We know that,

In ΔADO,

∠ADO + ∠DAO + ∠DOA = 180° 

= 90° + 35° + ∠DOA = 180° 

= 125° + ∠DOA = 180° 

= ∠DOA = 180° – 125° 

= ∠DOA = 55° 

Now, ∠DOA = ∠BOE = 55° 

In ΔBOE,

∠BOE + ∠OEB + ∠EBO = 180° 

= 55° + ∠OEB + 45° = 180° 

= ∠OEB = 180° – 45° – 55° 

= ∠OEB = ∠AEB = 80°