In an LC oscillator, C = 50 μF and L = 0.08 H are used. If the resistance of the circuit is negligible, the time period of oscillation is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 12.56 ms
Formula for time period of LC oscillator:
$T = 2\pi\sqrt{LC}$
Given: $L = 0.08 \ \text{H}, \ C = 50 \ \mu F = 50 \times 10^{-6} \ \text{F}$
$LC = 0.08 \times 50 \times 10^{-6} = 4.0 \times 10^{-6}$
$\sqrt{LC} = \sqrt{4.0 \times 10^{-6}} = 2.0 \times 10^{-3}$
$T = 2\pi \times 2.0 \times 10^{-3} = 4\pi \times 10^{-3} \ \text{s}$
$T \approx 0.0126 \ \text{s}$
${1.26 \times 10^{-2} \ \text{s}}$