Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Options:

a

b

c

d

Correct Answer:

c

Explanation:

$\text{From Energy Conservation } K_i + U_i = K_f + U_f $

$ K_i = 0 , K_f = k_1 + K_2 = 2K $

$ 0 - \frac{q^2}{4\pi \epsilon_0 r_1} = 2K - \frac{q^2}{4\pi \epsilon_0 r_2} $

$ 2K = \frac{q^2}{4\pi \epsilon_0 r_2} - \frac{q^2}{4\pi \epsilon_0 r_1}= mv^2 $

$ v = 0.3m/s$