Practicing Success
A train covers a distance in 50 min, if it runs at a speed of 48 kmph on an average. The speed at which the train must run to reduce the time of journey to 40 min will be.
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18 kmph 60 kmph 30 kmph 50 kmph |
60 kmph |
Speed = \(\frac{ Distance}{ Time}\) 48 km/hr = \(\frac{ Distance}{ \text{5/6 hr} }\) Distance = 48 x \(\frac{5 }{6 }\) Distance = 40 km Speed at which the train must run to reduce the time of journey to 40 min Speed = \(\frac{40km}{ 4/6hr}\) Speed = \(\frac{240km}{ 4hr}\) Speed = 60 km/hr |