Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Time, Speed and Distance

Question:

A train covers a distance in 50 min, if it runs at a speed of 48 kmph on an average. The speed at which the train must run to reduce the time of journey to 40 min will be.

 

Options:

18 kmph

60 kmph

30 kmph

50 kmph

Correct Answer:

60 kmph

Explanation:

Speed = \(\frac{ Distance}{ Time}\)

48 km/hr = \(\frac{ Distance}{ \text{5/6 hr} }\) 

Distance = 48 x \(\frac{5 }{6 }\)

Distance = 40 km

Speed at which the train must run to reduce the time of journey to 40 min

Speed = \(\frac{40km}{ 4/6hr}\)

Speed = \(\frac{240km}{ 4hr}\)

Speed = 60 km/hr