A spherical ball of diameter 35 cm rolls 20 times. How much is the distance (in m) covered by it?(Take $π =\frac{22}{7}$)
Answer & explanation
Correct answer: option 1
We know that,
Distance covered = 2πr × number of revolution.
We have,
Diameter of the spherical ball = 35 cm.
Then the radius = \(\frac{35}{2}\)
No. of revolutions of the ball = 20
Distance covered by spherical ball =2 × \(\frac{22}{7}\) × \(\frac{35}{2}\) × 20 = 2200 cm = 22 m