A spherical ball of diameter 35 cm rolls 20 times. How much is the distance (in m) covered by it?(Take $π =\frac{22}{7}$)

22

We know that,

Distance covered = 2πr × number of revolution.

We have,

Diameter of the spherical ball = 35 cm.

Then the radius = \(\frac{35}{2}\)

No. of revolutions of the ball = 20

Distance covered by spherical ball =2 × \(\frac{22}{7}\) × \(\frac{35}{2}\) × 20 = 2200 cm = 22 m