Linear equations $3x+5y=19$ and $10x-3y=24$ have solution $x =\frac{α}{3}$ and $y =\frac{β}{2}$, then the value of $α+β$ is:
Answer & explanation
Correct answer: option 2
3x + 5y = 19 ----(1)
10x - 3y = 24 ----(2)
Multiply equation 1 by 3 and equation 2 by 5 , and then add them
( 3x + 5y = 19 ) × 3
( 10x - 3y = 24 ) × 5
9x + 15y = 57
50x - 15y = 120
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59x = 177
x = 3
Now, Put value of x into equation 1
3 × 3 + 5y = 19
5y = 10
y = 2
Now, x = \(\frac{α}{3}\) , y = \(\frac{β}{2}\)
3 = \(\frac{α}{3}\) , 2 = \(\frac{β}{2}\)
So, α = 9 , β= 4
Now, α + β = 9 + 4 = 13