The value of $\frac{(793+232)^2-(793-232)^2}{(793×232)}$ is
Answer & explanation
Correct answer: option 2
(a + b)2 = a2 + b2 + 2ab
(a - b)2 = a2 + b2 - 2ab
(a + b)2 - (a - b)2 = (a2 + b2 + 2ab) - (a2 + b2 - 2ab) = 4ab
Using this formula in,
$\frac{(793+232)^2-(793-232)^2}{(793×232)}$ = $\frac{4 × 793 × 232}{(793×232)}$ = 4