The value of \(\frac{(793+232)^2-(793-232)^2}{(793\times232)}\) is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 4
The numerator has the form \((a+b)^2-(a-b)^2\), which always equals \(4ab\): the \(a^2\) and \(b^2\) terms cancel and the two \(2ab\) terms add up.
With \(a=793\) and \(b=232\), the numerator is \(4\times793\times232\)
\(\displaystyle \frac{4\times793\times232}{793\times232}=4\)