Practicing Success
The area of the region $A = \{(x,y): 0 ≤ y ≤ x|x|+1\, and\, -1 ≤x≤1\}$ in square units, is |
2/3 1/3 2 4/3 |
2 |
$y=x|x|+1,-1≤x≤1$ $⇒y=\left\{\begin{matrix}-x2+1,& -1≤x≤1\\x2+1,&0≤x≤1\end{matrix}\right.$ The required area A is given by $A=\int\limits_{-1}^0(-x^2+1)dx+\int\limits_0^1(x^2+1)dx$ $⇒A=\left[-\frac{x^3}{3}+x\right]_{-1}^0+\left[\frac{x^3}{3}+x\right]_0^1=2$ sq. units. |