For a Binomial distribution B (n, p), $\frac{E(x)}{V(x)}$ is equal to :
(symbols have their usual meaning)
Answer & explanation
Correct answer: option 4
For B (n, p)
$E(x)=np$
$V(x)=np(1-p)$
so $\frac{E(x)}{V(x)}=\frac{np}{np(1-p)}=\frac{1}{1-p}$
For a Binomial distribution B (n, p), $\frac{E(x)}{V(x)}$ is equal to :
(symbols have their usual meaning)
Correct answer: option 4
For B (n, p)
$E(x)=np$
$V(x)=np(1-p)$
so $\frac{E(x)}{V(x)}=\frac{np}{np(1-p)}=\frac{1}{1-p}$