A stationary cylinder of oxygen used in a hospital has the following characteristics at room temperature 300 K, gauge pressure 1.38 x 107 Pa, volume 16 L. If the flow area, measured a atmospheric pressure, is constant at 2.4 L/min, the cylinder will last for nearly : 

15 h

\(\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}\)

$\frac{1.38\times10^7 \times 16 }{300 K} = \frac{10^5 \times 2.4 t }{300 K}$

$t = \frac{1.38\times 10^7\times 16}{10^5\times 2.4} = 920 min$

$t = \frac{920}{60}h \approx 15h$