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If $1-64 x^3-12 x+p x^2=(1-4 x)^3$, then the value of p is: |
48 -12 -48 16 |
48 |
1 – 64x3 – 12x + px2 = (1 – 4x)3 = 1 – 64x3 – 12x + px2 = 1 – 64x3 – 3 × 1 × 4x (1 – 4x) = 1 – 64x3 – 12x + px2 = 1 – 64x3 – 12x + 48x2 = px2 = 48x2 = p = 48 |
