In a ΔABC, DE is parallel to BC where D and E are the points on AB and AC, respectively and AD = 4 cm, DB = 8 cm, AE = 3 cm. Length of EC is :
Answer & explanation
Correct answer: option 2
We know that,
If ΔABC ∼ ΔADE, then
AB/AD = BC/DE = AC/AE
We have,
AD = 4 cm
DB = 8 cm and AE = 3 cm.
Now,
\(\frac{ AD }{AB}\) = \(\frac{ AE }{AC}\)
= \(\frac{ 4 }{12}\) = \(\frac{ 3 }{AC}\)
= AC = 9cm
then, EC = 6 cm