CUET Preparation Today
CUET
-- Mathematics - Section B1
Application of Integrals
Area bounded by the curve $|x|+|y|=1$ is:
$\frac{1}{2}$
2
4
$\frac{1}{4}$
The correct answer is Option (2) - 2
$|x|+|y|=1$
area I = area II = area III = area IV By symmetry
area = 4 × area I
$4×\frac{1}{2}×1×1$
= 2 sq. units
