In the given figure, PQRS is a rectangle and A is point on SR such that QR = 24 cm and SA = 10 cm. If PA produced intersects QR produced at B, then find the length of PB.

39

ΔABR ∼ ΔPSA

\(\frac{AR}{SA}=\frac{RB}{PS}=\frac{5}{10}=\frac{1}{2}\)

\(RB=\frac{1}{2}×24=12cm\)

QB = 24 + 12 = 36 cm

By using triplet (5, 12, 13) × 3 = (15, 36, 39)

PB = 39 cm