The sum of the present ages of A and B is 80 years. Fourteen years ago, the ratio of the ages of A and B was 7 : 6. What is the present age of A?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 42 years
Fourteen years ago each was 14 years younger, so the sum then was 28 years less. That sum was shared in the ratio 7 : 6.
Sum fourteen years ago \(=80-2\times14=52\) years
A fourteen years ago \(\displaystyle=\frac{7}{13}\times52=28\) years
A now \(=28+14=42\) years