In a ΔABC, points P, Q and R are taken on AB, BC and CA, respectively, such that BQ = PQ and QC = QR. If ∠BAC = 75o, what is the measure of ∠PQR (in degrees)?
Answer & explanation
Correct answer: option 2

Calculation
∠BAC = 75o
∠ABC + ∠ACB + ∠BAC = 180o
∠ABC + ∠ACB + 75o = 180o
∠ABC + ∠ACB = 105o
Let, ∠ABC = ∠PBQ = 70o and ∠ACB = ∠RCQ = 35o
So, ∠PQR =180o - (∠PBQ + ∠RCQ)
⇒ 180o - [(180o - 2∠PBQ) + (180o - 2∠RCQ)] (as BQ = PQ, QC = QR)
⇒ 180o - [(180o - 2 x 70o) + (180o - 2 x 35o)]
⇒ 180o - (40o + 110o)
⇒ 180o - 150o
⇒ 30o
Therefore, ∠PQR is 30o.