If A and B are any two events such that P(B) = P(A and B), then which of the following is correct |
$P(B|A) = 1$ $P(A|B) = 1$ $P(B|A) = 0$ $P(A|B) = 0$ |
$P(A|B) = 1$ |
The correct answer is Option (2) → $P(A|B) = 1$ $P(B)=P(A\cap B)$ $P(A\mid B)=\frac{P(A\cap B)}{P(B)}$ $P(A\cap B)=P(B)$ gives $P(A\mid B)=\frac{P(B)}{P(B)}$ $P(A\mid B)=1$ B is therefore a subset of A because B occurs only when A occurs. Final answer: $P(A\mid B)=1$ |