If $x + y + z = 10, x^2 + y^2 + z^2 = 30$, then the value of $x^3 + y^3 + z^3 - 3xyz$ is __________.
Answer & explanation
Correct answer: option 4
If x + y = n
then, $x^3 + y^3$ = n3 - 3 × n × xy
we also know that,
If $K+ l=n$
then, $K^2+l^2$ = n2 – 2 × k × l
$x + y + z = 10, x^2 + y^2 + z^2 = 30$
Then the value of $x^3 + y^3 + z^3 - 3xyz$
If the number of equations are less than the number of variables then we can put the extra variables according to our choice =
So here two equations given and three variables are present so put z = 0
$x + y = 10, x^2 + y^2 = 30$
$x^2 + y^2$ = n2 – 2 × x × y
30 = 102 – 2 × xy
xy = 35
Then the value of $x^3 + y^3$ = 103 - 3 × 10 × 35
$x^3 + y^3$ = 1000 - 1050 = -50