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The value of tan-11+ tan-12 +tan-13 is |
0 1 π -π |
π |
We have tan-11+ tan-12 +tan-13 = tan‑11 + π + tan-1$(\frac{2+3}{1-2× 3})$ (since 2 × 3 > 1) = tan-11 + π + tan-1$(-\frac{5}{5})$ = tan-11 + π- tan-11 = π Hence (C) is the correct answer. |
