For a Poisson distribution, find $P(3)$, given $λ =\frac{1}{2}$.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 0.013
For a Poisson distribution,
$P(r) =\frac{λ^re^{-λ}}{r!}$
$P(3)=\frac{(\frac{1}{2})^3.e^{-0.5}}{3!}=\frac{\frac{1}{8}×0.607}{6}$ [$∵e^{-0.5}=0.607$, from table]
$=\frac{0.607}{48}= 0.013$