CUET Preparation Today
For a Poisson distribution, find $P(3)$, given $λ =\frac{1}{2}$. |
0.010 0.013 0.08 1.002 |
0.013 |
The correct answer is Option (2) → 0.013 For a Poisson distribution, $P(r) =\frac{λ^re^{-λ}}{r!}$ $P(3)=\frac{(\frac{1}{2})^3.e^{-0.5}}{3!}=\frac{\frac{1}{8}×0.607}{6}$ [$∵e^{-0.5}=0.607$, from table] $=\frac{0.607}{48}= 0.013$ |
