The domain of the real valued function f(x) for which $4^{f(x)}+4^{1-f(x)}=4^x$ is
Answer & explanation
Correct answer: option 2
$4^{f(x)}+\frac{4}{4^{f(x)}}=4^x$
$(4^{f(x)})^2-4^{xf(x)}+4=0⇒u^2-4^xu+4=0\,\,\,∵D≥0$
$4^{2x}≥4^2⇒2x≥2⇒x≥1$
The domain of the real valued function f(x) for which $4^{f(x)}+4^{1-f(x)}=4^x$ is
Correct answer: option 2
$4^{f(x)}+\frac{4}{4^{f(x)}}=4^x$
$(4^{f(x)})^2-4^{xf(x)}+4=0⇒u^2-4^xu+4=0\,\,\,∵D≥0$
$4^{2x}≥4^2⇒2x≥2⇒x≥1$