Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(II), (B)-(III), (C)-(IV), (D)-(I) (A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(A)-(II), (B)-(III), (C)-(IV), (D)-(I) |
The correct answer is Option (1) → (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
A. Thalassemia is an autosome-linked recessive blood disease transmitted from parents to the offspring when both the partners are unaffected carrier for the gene (or heterozygous). The defect could be due to either mutation or deletion which ultimately results in reduced rate of synthesis of one of the globin chains (α and β chains) that make up haemoglobin. This causes the formation of abnormal haemoglobin molecules resulting into anaemia which is characteristic of the disease. Thalassemia can be classified according to which chain of the haemoglobin molecule is affected. B. Sickle-cell anaemia: This is an autosome-linked recessive trait that can be transmitted from parents to the offspring when both the partners are carrier for the gene (or heterozygous). The disease is controlled by a single pair of allele, HbA and HbS. Out of the three possible genotypes, only homozygous individuals for HbS (HbSHbS) show the diseased phenotype. The defect is caused by the substitution of Glutamic acid (Glu) by Valine (Val) at the sixth position of the beta globin chain of the haemoglobin molecule. C. Klinefelter’s Syndrome : This genetic disorder is also caused due to the presence of an additional copy of X- chromosome resulting into a karyotype of 47, XXY. Such an individual has overall masculine development, however, the feminine development (development of breast, i.e., Gynaecomastia) is also expressed. Such individuals are sterile. D.Turner’s Syndrome : Such a disorder is caused due to the absence of one of the X chromosomes, i.e., 45 with XO, Such females are sterile as ovaries are rudimentary besides other features including lack of other secondary sexual characters. |