Match List-I with List-II
| List-I | List-II |
|---|---|
| Genetic disorder | Cause |
| (A) Thalassemia | (I) 45+XO |
| (B) Sickle-cell anemia | (II) Formation of abnormal hemoglobin |
| (C) Klinefelter's syndrome | (III) Substitution of glutamic acid by valine |
| (D) Turner's syndrome | (IV) 47, XXY |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
(A) Thalassemia — this matches (II) Formation of abnormal hemoglobin. Less of one globin chain is made, so abnormal haemoglobin forms and the person becomes anaemic.
(B) Sickle-cell anemia — this matches (III) Substitution of glutamic acid by valine. One base change in the β-globin gene puts valine in place of glutamic acid at the sixth position, and the red cells turn sickle-shaped at low oxygen.
(C) Klinefelter’s syndrome — this matches (IV) 47, XXY. The male has one extra X chromosome; he is sterile and may develop breasts.
(D) Turner’s syndrome — this matches (I) 45+XO. The female has only one X chromosome; her ovaries do not develop.