The mean of the number of heads in a simultaneous toss of three coins is

$\frac{3}{2}$

The correct answer is Option (1) → $\frac{3}{2}$ **

$\text{Let }X=\text{ number of heads in 3 tosses.}$

$X\text{ takes values }0,1,2,3\text{ with binomial distribution }B(3,\frac{1}{2}).$

$\text{Mean of a binomial distribution}=np$

$=3\cdot\frac{1}{2}$

$=\frac{3}{2}$

The mean of the number of heads is $\frac{3}{2}$.