Practicing Success
Practicing Success
CUET Preparation Today
If in a nuclear fission, piece of uranium of mass 0.5 g is lost, the energy obtained in kWh is |
$1.25 \times 10^7$ $2.25 \times 10^7$ $3.25 \times 10^7$ $0.25 \times 10^7$ |
$1.25 \times 10^7$ |
$E=\Delta m c^2=0.5 \times 10^{-3} \times\left(3 \times 10^8\right)^2=4.5 \times 10^{13} J$ $\Rightarrow E=\frac{4.5 \times 10^{13}}{3.6 \times 10^6}=1.25 \times 10^7 \mathrm{kWH}$. |
