If in a nuclear fission, piece of uranium of mass 0.5 g is lost, the energy obtained in kWh is
Answer & explanation
Correct answer: option 1
$E=\Delta m c^2=0.5 \times 10^{-3} \times\left(3 \times 10^8\right)^2=4.5 \times 10^{13} J$
$\Rightarrow E=\frac{4.5 \times 10^{13}}{3.6 \times 10^6}=1.25 \times 10^7 \mathrm{kWH}$.