Let ABC be a triangle having its centroid at G. If S is any point in the plane of the triangle, then $\vec{SA} + \vec{SB} + \vec{SC} =$
Answer & explanation
Correct answer: option 3
We have,
$\vec{SA} + \vec{SB} + \vec{SC} =\vec{SA} +(\vec{SB} + \vec{SC})$
$⇒\vec{SA} + \vec{SB} + \vec{SC} =\vec{SA} +2\vec{SD}=(1+2)\vec{SG}=3\vec{SG}$
