Practicing Success
Practicing Success
CUET Preparation Today
Let ABC be a triangle having its centroid at G. If S is any point in the plane of the triangle, then $\vec{SA} + \vec{SB} + \vec{SC} =$ |
$\vec{SG}$ $2\vec{SG}$ $3\vec{SG}$ $\vec{0}$ |
$3\vec{SG}$ |
We have, $\vec{SA} + \vec{SB} + \vec{SC} =\vec{SA} +(\vec{SB} + \vec{SC})$ $⇒\vec{SA} + \vec{SB} + \vec{SC} =\vec{SA} +2\vec{SD}=(1+2)\vec{SG}=3\vec{SG}$
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