A solenoid of length $0.5 \mathrm{~m}$ and radius $10 \mathrm{~cm}$ has 500 turns. If a current of $5 \mathrm{~A}$ flows through it, the magnetic field produced inside the solenoid will be:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $6.28\times 10^{-3}T$
Given,
$l$, length of solenoid = 0.5 m
R, Radius of solenoid = 10 cm
N, Number of turns = 500 turns
I, Current = 5 A
$ n = \frac{N}{l} = \frac{500}{0.5} = 1000$
$ B = \mu_0 nI$
$= 4\pi \times 1000 \times 5$
$= 6.28\times 10^{-3}T$