A solenoid of length $0.5 \mathrm{~m}$ and radius $10 \mathrm{~cm}$ has 500 turns. If a current of $5 \mathrm{~A}$ flows through it, the magnetic field produced inside the solenoid will be:

6.28 × 10^-3 T

The correct answer is Option (4) → $6.28\times 10^{-3}T$

Given,

$l$, length of solenoid = 0.5 m

R, Radius of solenoid = 10 cm

N, Number of turns = 500 turns

I, Current = 5 A

$ n = \frac{N}{l} = \frac{500}{0.5} = 1000$

$ B = \mu_0 nI$

$= 4\pi \times 1000 \times 5$

$= 6.28\times 10^{-3}T$