CUET Preparation Today
Find the value of $\int\limits_{1}^{4} |x - 5| \, dx$ |
$\frac{9}{2}$ $\frac{15}{2}$ $\frac{7}{2}$ $-\frac{15}{2}$ |
$\frac{15}{2}$ |
The correct answer is Option (2) → $\frac{15}{2}$ $\int\limits_{1}^{4} |x - 5| \, dx = \int\limits_{1}^{4} -(x - 5) \, dx$ $= -\left[ \frac{1}{2}(x - 5)^2 \right]_{1}^{4}$ $\int\limits_{1}^{4} |x - 5| \, dx = -\frac{1}{2} [1 - 16] = \frac{15}{2}$ |
