If 3x = 9y = 81z and xyz = 1728, then find the value of y.

(3)^x = ((3)²)^y = ((3)⁴)^z

3^x = 3^2y = 3^4z

So, in this condition, if base is same, then power will be equal

x = 2y = 4z

x = 4R    

y = 2R     

z = R         

Now, xyz = 1728

4R×2R×R = 1728

8R³ = 1728

R³ = 216

R = 6

y =2×6 = 12