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For a second-order reaction, If the concentration of reactant is increased by four times, what will be the increase in the rate of formation of the product? |
4 times 8 times 16 times 32 times |
16 times |
| For a second order reaction
Rate = k [A]2 if we increase the reactant by four times, then rate = k[4A]2 =16k[A]2 |
