The position of a point in time \('t'\) is given by \(x=a+bt-ct^2, y=at+bt^2\). Is acceleration at time \('t'\) is1\(t-c\)2\(t+c\)3\(2t-2c\)4\(2\sqrt{t^2+c^2}\)Answer & explanation+Correct answer: option 4Use derivatives
