The position of a point in time $'t'$

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

The position of a point in time $'t'$ is given by $x=a+bt-ct^2, y=at+bt^2$. Is acceleration at time $'t'$ is

Options:

$t-c$

$t+c$

$2t-2c$

$2\sqrt{t^2+c^2}$

Correct Answer:

$2\sqrt{t^2+c^2}$

Explanation:

Use derivatives