Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:
The position of a point in time \('t'\) is given by \(x=a+bt-ct^2, y=at+bt^2\). Is acceleration at time \('t'\) is
Options:
\(t-c\)
\(t+c\)
\(2t-2c\)
\(2\sqrt{t^2+c^2}\)
Correct Answer:
\(2\sqrt{t^2+c^2}\)
Explanation:
Use derivatives