CUET Preparation Today
For the L-R series circuit connected to an ac mains $e=e_0\sin ωt$, the average power consumed is: (Symbols have their usual meanings) |
$\frac{e_0^2R}{2(R^2+ω^2L^2)}$ $\frac{e_0^2L}{2(R^2+ω^2L^2)}$ $\frac{e_0^2}{2(R^2+ω^2L^2)}$ $\frac{e_0^2}{(R^2+ω^2L^2)}$ |
$\frac{e_0^2R}{2(R^2+ω^2L^2)}$ |
The correct answer is Option (1) → $\frac{e_0^2R}{2(R^2+ω^2L^2)}$ |
