What is the probability of getting a sum of 9 from two throws of a dice? |
$\frac{1}{3}$ $\frac{1}{6}$ $\frac{1}{9}$ $\frac{1}{12}$ |
$\frac{1}{9}$ |
When a die is thrown the outcome can be any of the numbers from 1 to 6. If two dice are thrown the set of outcomes that ensure the sum is 9 is {(3, 6), (6,3), (4, 5), (5, 4)}. The total number of possible outcomes is 6*6 = 36 This gives the required probability as 4/36 = 1/9 |