Two spheres each of mass M and radius R/2 are connected with a mass less rod of length 2R as shown in figure. What will be moment of inertia of the system about an axis passing through centre of one of the spheres and perpendicular to the rod?
Answer & explanation
Correct answer: option 4
Moment of Inertia about yy1 = I
I = (2/5) M(R / 2)2 + (2/5) M(R / 2)2 + M(2R)2
as Moment of Inertia of sphere = (2/5)MR2
hence I = (4/5) M ∙ (R2 / 4) + 4R2M
= 4MR2[{1 / (20)} + 1]
= (21 / 5)MR2