Which of the following is a by product of the reaction between fluoroborate diazonium salt and sodium nitrite in the presence of copper?
Answer & explanation
Correct answer: option 1
The correct answer is option 1. \(NaBF_4\)
Let us delve into the reaction why \(NaBF_4\) is the correct by-product.
The reaction between a fluoroborate diazonium salt and sodium nitrite in the presence of copper generally involves the replacement of the diazonium group. Here's a more detailed look at the process:
Reaction Mechanism:
Starting Materials:
Fluoroborate diazonium salt: \((ArN_2^+ BF_4^-)\)
Sodium nitrite: \((NaNO_2)\)
Copper: \(Cu\)
Reaction Process: The diazonium salt can undergo a Sandmeyer-like reaction or similar copper-catalyzed decomposition. The diazonium group \((N_2^+)\) is replaced by another group through the action of the copper catalyst.
Products: During the reaction, the diazonium group is replaced, and \(BF_4^-\) (tetrafluoroborate) ion is released. This \(BF_4^-\) ion can combine with \(Na^+\) from sodium nitrite to form sodium tetrafluoroborate (NaBF4).
Balanced Reaction:
\(ArN_2^+ BF_4^- + NaNO_2 + Cu \rightarrow Ar + N_2 + NaBF_4 \)
The replacement of the diazonium group leads to the release of nitrogen gas \((N_2)\).
The \(BF_4^-\) ion from the fluoroborate diazonium salt pairs with \(Na^+\) ions from sodium nitrite, resulting in the formation of \(NaBF_4\).
Therefore, the by-product of the reaction is indeed: \(NaBF_4\)