Two vessels P and Q contain milk and water in the ratio 5 : 3 and 13 : 3 respectively. In what ratio mixtures from two vessels should be mixed to get a new mixture containing milk and water in the ratio 3 : 1 respectively ? |
1: 3 1 : 2 2 : 3 3 : 2 |
1 : 2 |
The correct answer is option (2) : 1 : 2 Quantity of milk in mixture $P=\frac{5}{18}$ part Quantity of milk in mixture $Q=\frac{13}{6}$ part Quantity of milk in new mixture $=\frac{3}{14}$ part LCM of 8, 16 and 4 = 16. So, quantity of milk in mixture $p=\frac{5×2}{8×2}=\frac{10}{6}$ part quantity of milk in mixture $Q=\frac{13}{6}$part quantity of milk in new mixture $=\frac{3×4}{4×4}= \frac{12}{16}$ part $∴\frac{}{}=\frac{1/16}{2/16}=\frac{1}{2}$ $= 1: 2$
|