Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

If m is the degree and n is the order of the given differential equation

\(\frac{x^3\left(\frac{d^3 y}{d x^3}\right)^2+2 x^2\left(\frac{d^2 y}{d x^2}\right)^3}{(x+1)^5}=\left(3 x-\frac{d^2 y}{d x^2}\right)^4 \)

Options:

m – n = 2

m + n = 5

m = 4, n = 3

Order (n) is 3 but degree (m) is not defined

Correct Answer:

m + n = 5

Explanation:

\(\frac{x^3\left(\frac{d^3 y}{d x^3}\right)^2+2 x^2\left(\frac{d^2 y}{d x^2}\right)^3}{(x+1)^5}=\left(3 x-\frac{d^2 y}{d x^2}\right)^4 \)

$⇒x^3(\frac{d^3 y}{d x^3})^2+2x^2(\frac{d^2 y}{d x^2})^3-(x+1)^5(3x-\frac{d^2 y}{d x^2})^4=0$

∴ order (n) = 3

Degree (m) = 2

∴ m + n = 5 

option 2 is correct.