CUET Preparation Today
An electric bulb rated 100 W at 200 V is connected to a 160 V power supply. The power consumed by it would be: |
64 W 80 W 100 W 125 W |
64 W |
The correct answer is Option (1) → 64 W The power consumed, $P=\frac{V^2}{R}$ $⇒R=\frac{V^2}{P}=\frac{(200)^2}{100}=400Ω$ Now the bulb is connected to 160 V power supply. $P=\frac{V^2}{R}=\frac{(160)^2}{400}=64W$ |
