The liquids X and Y are mixed in the ratio of 6 : 5 and the mixture is sold at Rs. 11 p/ltr at a profit of 10%.  If the liquid X costs Rs. 2 more p/ltr then Y, then cost of X per liter is:

8.90

Let cost of Y = n, then cost of X = n + 2

X : Y = 6 : 5 = 11 (total)

Total cost of X and Y = 6 (n + 2) + 5 (n)

S.P. of total liquid = 6 (n + 2) + 5 (n) × 110%

ATQ, S.P. of mixture = Rs.11 per ltr

Hence,

⇒ 6 (n + 2) + 5 (n) × \(\frac{110}{100}\) = 11 × 11               (6 + 5 = 11 total quantity)

⇒ 6 (n + 2) + 5 (n) = 121 × \(\frac{100}{110}\)

⇒ 6n + 12 + 5n = 10 × 11

⇒ 11n = 110 - 12

n = \(\frac{98}{11}\) = Rs. 8.90 per ltr.