The liquids X and Y are mixed in the ratio of 6 : 5 and the mixture is sold at Rs. 11 p/ltr at a profit of 10%. If the liquid X costs Rs. 2 more p/ltr then Y, then cost of X per liter is:
Answer & explanation
Correct answer: option 3
Let cost of Y = n, then cost of X = n + 2
X : Y = 6 : 5 = 11 (total)
Total cost of X and Y = 6 (n + 2) + 5 (n)
S.P. of total liquid = 6 (n + 2) + 5 (n) × 110%
ATQ, S.P. of mixture = Rs.11 per ltr
Hence,
⇒ 6 (n + 2) + 5 (n) × \(\frac{110}{100}\) = 11 × 11 (6 + 5 = 11 total quantity)
⇒ 6 (n + 2) + 5 (n) = 121 × \(\frac{100}{110}\)
⇒ 6n + 12 + 5n = 10 × 11
⇒ 11n = 110 - 12
n = \(\frac{98}{11}\) = Rs. 8.90 per ltr.