The least six digits numbers which is divided by 5, 15, 25, 30 leaves in each case same remainder 2 be N. Sum of the digits in N is:
Answer & explanation
Correct answer: option 4
L.C.M. of 5, 15, 25, 30 = 150
Least number of six digits = 100000
Dividing 100000 by 150 we get remainder = 100
∴ Least number of six digits divisible by 5, 15, 25, 30
= 100000 + (150 - 100) = 100050
∴ N = 100050 + 2 = 100052
∴ Sum of digits in N = 1 + 0 + 0 + 0 + 5 + 2 = 8