Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

HCF and LCM

Question:

The least six digits numbers which is divided by 5, 15, 25, 30 leaves in each case same remainder 2 be N. Sum of the digits in N is:

Options:

5

6

7

8

Correct Answer:

8

Explanation:

L.C.M. of 5, 15, 25, 30 = 150

Least number of six digits = 100000

Dividing 100000 by 150 we get remainder = 100

∴ Least number of six digits divisible by 5, 15, 25, 30

 = 100000 + (150 - 100) = 100050

∴ N = 100050 + 2 = 100052

∴ Sum of digits in N = 1 + 0 + 0 + 0 + 5 + 2 = 8