Two dice are tossed together. The odds in favour of the sum of the numbers on them as 2 are
Answer & explanation
Correct answer: option 2
If two dice are tossed, total number of events = 6 × 6 = 36.
Favourable event is (1, 1). Number of favourable events = 1
∴ odds in favour $=\frac{1}{36-1}=\frac{1}{35}.$