Two dice are tossed together. The odds in favour of the sum of the numbers on them as 2 are

1 : 36 1 : 35 35 : 1 None of these

1 : 35

If two dice are tossed, total number of events = 6 × 6 = 36. Favourable event is (1, 1). Number of favourable events = 1 ∴ odds in favour $=\frac{1}{36-1}=\frac{1}{35}.$