CUET Preparation Today
Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(I), (B)-(II), (C)-(III), (D)-(IV) (A)-(I), (B)-(III), (C)-(II), (D)-(IV) (A)-(I), (B)-(II), (C)-(IV), (D)-(III) (A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
(A)-(III), (B)-(IV), (C)-(I), (D)-(II) |
The correct answer is Option (4) → (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
(A) Gattermann–Koch reaction $\rightarrow$ (III) $\text{CO}, \text{HCl}, \text{AlCl}_3/\text{CuCl}$ This reaction introduces a formyl group ($-\text{CHO}$) into an aromatic ring. $\text{CO}$ and $\text{HCl}$ in the presence of $\text{AlCl}_3/\text{CuCl}$ generate the electrophile needed for formylation.
(B) Rosenmund reduction $\rightarrow$ (IV) $\text{H}_2 / \text{Pd}-\text{BaSO}_4$ Used to convert acid chlorides into aldehydes. The Palladium catalyst is poisoned with $\text{BaSO}_4$ to prevent further reduction to alcohol.
(C) Etard reaction $\rightarrow$ (I) $\text{CrO}_2\text{Cl}_2$ / $\text{CS}_2$ This reaction oxidizes the methyl group attached to benzene to an aldehyde. Chromyl chloride is the characteristic reagent.
(D) Friedel–Crafts acylation $\rightarrow$ (II) Acyl chloride/anhydride + $\text{AlCl}_3$ Introduces an acyl group ($-\text{COR}$) into an aromatic ring. $\text{AlCl}_3$ acts as a Lewis acid to generate the acylium ion electrophile.
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