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CUET
General Test
Numerical Ability
Ratios
If $\frac{2a^2-3b^2}{a^2+b^2}=\frac{2}{41}$, then $a:b$ =
5 : 4
25 : 16
16 : 25
4 : 5
Given,
$\frac{2a^2-3b^2}{a^2+b^2}=\frac{2}{41}$
82a2 - 123b2 = 2a2 + 2b2
= 80a2 = 125b2
= a2 : b2 = 25 : 16
a : b = 5 : 4