If \(y=e^{-x}(A \cos x+B \sin x)\), then \(y\) is a solution of1\(\frac{d^2 y}{dx^2}+2\frac{dy}{dx}=0\)2\(\frac{d^2 y}{dx^2}-2\frac{dy}{dx}+2y=0\)3\(\frac{d^2 y}{dx^2}+2\frac{dy}{dx}+2y=0\)4\(\frac{d^2 y}{dx^2}+2y=0\)Answer & explanation+Correct answer: option 3\(y\) satisfies equation given in (c).
