The specific resistance \(\rho\) of a circular wire of radius r, resistance R, and length l is given by \(\rho = \frac{\pi r^2R}{l}\). Given : r = (0.24 \(\pm\) 0.02) cm, R = (30 \(\pm 1) \Omega\) and l = (4.80 \(\pm\) 0.01) cm. The percentage error in \(\rho\) is nearly : 

20%

Required percentage = \(2*\frac{0.02}{0.24}*100 +\frac{1}{30}*100 + \frac{0.01}{4.80}*100\)

                              = (16.7 + 3.3 + 0.2)% = 20%