80 liters of a mixture of alcohol and water contains 60% alcohol. If 'X' liters of water is added to this mixture, then the percentage of alcohol in the new mixture becomes 40%. What is the value of X?
Answer & explanation
Correct answer: option 3
Initial solution,
Alcohol : Water
3 : 2 ..(1)
After adding X liters water, Final solution,
Alcohol : Water
2 : 3 ..(2)
⇒ Making ratio of Alcohol in both solution equal, we multiply (1) with 2 and (2) with 3.
⇒ (3 : 2) x 2 = 6 : 4, and (2 : 3) x 3 = 6 : 9,
⇒ Difference between After water and initial water ratio = 9 - 4 = 5 units.
⇒ Quantity of initial solution = 80 liters,
⇒ (6 + 4) units = 80,
⇒ 10 units = 80,
⇒ 1 unit = 8 liters,
Therefore, amount of water 'X' added is = 5 x 8 = 40 liters.