The peak value of the electric field associated with an electromagnetic wave traveling through vacuum is $8.1\, NC^{-1}$. The peak value of the associated magnetic field will be
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $2.7 × 10^{-8} T$
Given:
Peak electric field, $E_0 = 8.1\ \text{N/C}$
Speed of light, $c = 3\times10^8\ \text{m/s}$
Relation between electric and magnetic fields:
$\frac{E_0}{B_0} = c$
Hence, $B_0 = \frac{E_0}{c}$
Substitute values:
$B_0 = \frac{8.1}{3\times10^8} = 2.7\times10^{-8}\ \text{T}$
Therefore, the peak value of the magnetic field is
$B_0 = 2.7\times10^{-8}\ \text{T}$