A vessel contains a 32 liter solution of acid and water in which the ratio of acid and water is 5 : 3. If 12 liter of solution is taken out and 7\(\frac{1}{2}\) liter water is added then find the resultant ratio in new mixture.
Answer & explanation
Correct answer: option 4
Acid Water
5 : 3
(Ratio will remain same when we remove 'x (any quantity)' ltr. from the initial solution.)
Here x = 12
Total Quantity = 32
After removing 12 liters = 32 - 12 = 20 liters
Acid + Water = 20
A : W = 5 : 3 = 8R → 20
1R → 2.5
3R = 7.5
Water added is = 7.5ltr = 3R
Now, ratio will be
Acid : Water = 5 : (3+3) = 5 : 6